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=3A(5A+8)=1
We move all terms to the left:
-(3A(5A+8))=0
We calculate terms in parentheses: -(3A(5A+8)), so:We get rid of parentheses
3A(5A+8)
We multiply parentheses
15A^2+24A
Back to the equation:
-(15A^2+24A)
-15A^2-24A=0
a = -15; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·(-15)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*-15}=\frac{0}{-30} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*-15}=\frac{48}{-30} =-1+3/5 $
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