A=2/3(B+C)

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Solution for A=2/3(B+C) equation: 


x in (-oo:+oo)

A = (2/3)*(B+C) // - (2/3)*(B+C)

A-((2/3)*(B+C)) = 0

(-2/3)*(B+C)+A = 0

A-2/3*(B+C) = 0

A-2/3*(B+C) = 0

A-2/3*B-2/3*C = 0

A-2/3*B-2/3*C = 0

x belongs to the empty set

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