A=10-(2x+5)

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Solution for A=10-(2x+5) equation:



=10-(2A+5)
We move all terms to the left:
-(10-(2A+5))=0
We calculate terms in parentheses: -(10-(2A+5)), so:
10-(2A+5)
determiningTheFunctionDomain -(2A+5)+10
We get rid of parentheses
-2A-5+10
We add all the numbers together, and all the variables
-2A+5
Back to the equation:
-(-2A+5)
We get rid of parentheses
2A-5=0
We move all terms containing A to the left, all other terms to the right
2A=5
A=5/2
A=2+1/2

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