A=1/2*(3x-2)(4x)

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Solution for A=1/2*(3x-2)(4x) equation:


x in (-oo:+oo)

A = 4*(1/2)*x*(3*x-2) // - 4*(1/2)*x*(3*x-2)

A-(4*(1/2)*x*(3*x-2)) = 0

A-2*x*(3*x-2) = 0

A-2*x*(3*x-2) = 0

A-6*x^2+4*x = 0

A-6*x^2+4*x = 0

A-6*x^2+4*x = 0

DELTA = 4^2-(-6*4*A)

DELTA = 24*A+16

24*A+16 = 0

24*A+16 = 0 // - 16

24*A = -16 // : 24

A = -16/24

A = -2/3

DELTA = 0 <=> t_3 = -2/3

x = -4/(-6*2) i A = -2/3

x = 1/3 i A = -2/3

( x = ((24*A+16)^(1/2)-4)/(-6*2) or x = (-(24*A+16)^(1/2)-4)/(-6*2) ) i A > -2/3

( x = ((24*A+16)^(1/2)-4)/(-12) or x = ((24*A+16)^(1/2)+4)/12 ) i A > -2/3

A+2/3 > 0

A+2/3 > 0 // - 2/3

A > -2/3

x in { 1/3, ((24*A+16)^(1/2)-4)/(-12), ((24*A+16)^(1/2)+4)/12 }

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