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=-4A(6-3A)
We move all terms to the left:
-(-4A(6-3A))=0
We add all the numbers together, and all the variables
-(-4A(-3A+6))=0
We calculate terms in parentheses: -(-4A(-3A+6)), so:We get rid of parentheses
-4A(-3A+6)
We multiply parentheses
12A^2-24A
Back to the equation:
-(12A^2-24A)
-12A^2+24A=0
a = -12; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-12)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-12}=\frac{-48}{-24} =+2 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-12}=\frac{0}{-24} =0 $
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