A=-32x2+1500x=0

Solution for A=-32x2+1500x=0 equation:

=-32A^2+1500A=0

We move all terms to the left:

-(-32A^2+1500A)=0

We get rid of parentheses

32A^2-1500A=0

a = 32; b = -1500; c = 0;
Δ = b2-4ac
Δ = -15002-4·32·0
Δ = 2250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2250000}=1500$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1500)-1500}{2*32}=\frac{0}{64}
=0
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1500)+1500}{2*32}=\frac{3000}{64}
=46+7/8
$