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=(3A+7)2A+3)
We move all terms to the left:
-((3A+7)2A+3))=0
We calculate terms in parentheses: -((3A+7)2A+3)), so:We get rid of parentheses
(3A+7)2A+3)
We add all the numbers together, and all the variables
(3A+7)2A
We multiply parentheses
6A^2+14A
Back to the equation:
-(6A^2+14A)
-6A^2-14A=0
a = -6; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-6)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-6}=\frac{0}{-12} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-6}=\frac{28}{-12} =-2+1/3 $
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