A=(2y-5)+(y+35)

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Solution for A=(2y-5)+(y+35) equation: 



=(2A-5)+(A+35)

We move all terms to the left:

-((2A-5)+(A+35))=0



We calculate terms in parentheses: -((2A-5)+(A+35)), so:

(2A-5)+(A+35)

We get rid of parentheses

2A+A-5+35

We add all the numbers together, and all the variables

3A+30

Back to the equation:

-(3A+30)



We get rid of parentheses

-3A-30=0

We move all terms containing A to the left, all other terms to the right

-3A=30

A=30/-3

A=-10

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