A=(20-2x)16+10x

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Solution for A=(20-2x)16+10x equation: 



=(20-2A)16+10A

We move all terms to the left:

-((20-2A)16+10A)=0

We add all the numbers together, and all the variables

-((-2A+20)16+10A)=0



We calculate terms in parentheses: -((-2A+20)16+10A), so:

(-2A+20)16+10A

We add all the numbers together, and all the variables

10A+(-2A+20)16

We multiply parentheses

10A-32A+320

We add all the numbers together, and all the variables

-22A+320

Back to the equation:

-(-22A+320)



We get rid of parentheses

22A-320=0

We move all terms containing A to the left, all other terms to the right

22A=320

A=320/22

A=14+6/11

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