A=(13x-5)(14x+)

Solution for A=(13x-5)(14x+) equation:

=(13A-5)(14A+)

We move all terms to the left:

-((13A-5)(14A+))=0

We add all the numbers together, and all the variables

-((13A-5)(+14A))=0

We multiply parentheses ..

-((+182A^2-70A))=0


We calculate terms in parentheses: -((+182A^2-70A)), so:

(+182A^2-70A)

We get rid of parentheses

182A^2-70A

Back to the equation:

-(182A^2-70A)


We get rid of parentheses

-182A^2+70A=0

a = -182; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·(-182)·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*-182}=\frac{-140}{-364}
=5/13
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*-182}=\frac{0}{-364}
=0
$