A2+b2=144

Solution for A2+b2=144 equation:

2+A2=144

We move all terms to the left:

2+A2-(144)=0

We add all the numbers together, and all the variables

A^2-142=0

a = 1; b = 0; c = -142;
Δ = b2-4ac
Δ = 02-4·1·(-142)
Δ = 568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{568}=\sqrt{4*142}=\sqrt{4}*\sqrt{142}=2\sqrt{142}$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{142}}{2*1}=\frac{0-2\sqrt{142}}{2}
=-\frac{2\sqrt{142}}{2}
=-\sqrt{142}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{142}}{2*1}=\frac{0+2\sqrt{142}}{2}
=\frac{2\sqrt{142}}{2}
=\sqrt{142}
$