A+8(1-7a)=-40-7a

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Solution for A+8(1-7a)=-40-7a equation: 



+8(1-7A)=-40-7A

We move all terms to the left:

+8(1-7A)-(-40-7A)=0

We add all the numbers together, and all the variables

8(-7A+1)-(-7A-40)=0

We multiply parentheses

-56A-(-7A-40)+8=0

We get rid of parentheses

-56A+7A+40+8=0

We add all the numbers together, and all the variables

-49A+48=0

We move all terms containing A to the left, all other terms to the right

-49A=-48

A=-48/-49

A=48/49

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