A+31/2s+10=64

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Solution for A+31/2s+10=64 equation: 



+31/2A+10=64

We move all terms to the left:

+31/2A+10-(64)=0



Domain of the equation: 2A!=0

A!=0/2

A!=0

A∈R



We add all the numbers together, and all the variables

31/2A-54=0

We multiply all the terms by the denominator


-54*2A+31=0

Wy multiply elements

-108A+31=0

We move all terms containing A to the left, all other terms to the right

-108A=-31

A=-31/-108

A=31/108

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