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(A)=A(200-3A)
We move all terms to the left:
(A)-(A(200-3A))=0
We add all the numbers together, and all the variables
A-(A(-3A+200))=0
We calculate terms in parentheses: -(A(-3A+200)), so:We get rid of parentheses
A(-3A+200)
We multiply parentheses
-3A^2+200A
Back to the equation:
-(-3A^2+200A)
3A^2-200A+A=0
We add all the numbers together, and all the variables
3A^2-199A=0
a = 3; b = -199; c = 0;
Δ = b2-4ac
Δ = -1992-4·3·0
Δ = 39601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{39601}=199$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-199)-199}{2*3}=\frac{0}{6} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-199)+199}{2*3}=\frac{398}{6} =66+1/3 $
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