A(x)=(2x+8)(2x+10)

Solution for A(x)=(2x+8)(2x+10) equation:

(A)=(2A+8)(2A+10)

We move all terms to the left:

(A)-((2A+8)(2A+10))=0

We multiply parentheses ..

-((+4A^2+20A+16A+80))+A=0


We calculate terms in parentheses: -((+4A^2+20A+16A+80)), so:

(+4A^2+20A+16A+80)

We get rid of parentheses

4A^2+20A+16A+80

We add all the numbers together, and all the variables

4A^2+36A+80

Back to the equation:

-(4A^2+36A+80)


We add all the numbers together, and all the variables

A-(4A^2+36A+80)=0

We get rid of parentheses

-4A^2+A-36A-80=0

We add all the numbers together, and all the variables

-4A^2-35A-80=0

a = -4; b = -35; c = -80;
Δ = b2-4ac
Δ = -352-4·(-4)·(-80)
Δ = -55
Delta is less than zero, so there is no solution for the equation