A(t-3)(t-5)=h(t)

Solution for A(t-3)(t-5)=h(t) equation:

Simplifying
A(t + -3)(t + -5) = h(t)

Reorder the terms:
A(-3 + t)(t + -5) = h(t)

Reorder the terms:
A(-3 + t)(-5 + t) = h(t)

Multiply (-3 + t) * (-5 + t)
A(-3(-5 + t) + t(-5 + t)) = h(t)
A((-5 * -3 + t * -3) + t(-5 + t)) = h(t)
A((15 + -3t) + t(-5 + t)) = h(t)
A(15 + -3t + (-5 * t + t * t)) = h(t)
A(15 + -3t + (-5t + t2)) = h(t)

Combine like terms: -3t + -5t = -8t
A(15 + -8t + t2) = h(t)
(15 * A + -8t * A + t2 * A) = h(t)
(15A + -8tA + t2A) = h(t)

Multiply h * t
15A + -8tA + t2A = ht

Solving
15A + -8tA + t2A = ht

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Reorder the terms:
15A + -1ht + -8tA + t2A = ht + -1ht

Combine like terms: ht + -1ht = 0
15A + -1ht + -8tA + t2A = 0

The solution to this equation could not be determined.