A(n)=4+(n-1)(-2)

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Solution for A(n)=4+(n-1)(-2) equation: 



(A)=4+(A-1)(-2)

We move all terms to the left:

(A)-(4+(A-1)(-2))=0

We multiply parentheses ..

A-(4+(-2A+2))=0



We calculate terms in parentheses: -(4+(-2A+2)), so:

4+(-2A+2)

determiningTheFunctionDomain
(-2A+2)+4

We get rid of parentheses

-2A+2+4

We add all the numbers together, and all the variables

-2A+6

Back to the equation:

-(-2A+6)



We get rid of parentheses

A+2A-6=0

We add all the numbers together, and all the variables

3A-6=0

We move all terms containing A to the left, all other terms to the right

3A=6

A=6/3

A=2

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