A(n)=2+(n-1)(5)

Solution for A(n)=2+(n-1)(5) equation:

(A)=2+(A-1)(5)

We move all terms to the left:

(A)-(2+(A-1)(5))=0


We calculate terms in parentheses: -(2+(A-1)5), so:

2+(A-1)5

determiningTheFunctionDomain
(A-1)5+2

We multiply parentheses

5A-5+2

We add all the numbers together, and all the variables

5A-3

Back to the equation:

-(5A-3)


We get rid of parentheses

A-5A+3=0

We add all the numbers together, and all the variables

-4A+3=0

We move all terms containing A to the left, all other terms to the right

-4A=-3

A=-3/-4

A=3/4