A(n)=-9+(n+1)(3)

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Solution for A(n)=-9+(n+1)(3) equation: 



(A)=-9+(A+1)(3)

We move all terms to the left:

(A)-(-9+(A+1)(3))=0



We calculate terms in parentheses: -(-9+(A+1)3), so:

-9+(A+1)3

determiningTheFunctionDomain
(A+1)3-9

We multiply parentheses

3A+3-9

We add all the numbers together, and all the variables

3A-6

Back to the equation:

-(3A-6)



We get rid of parentheses

A-3A+6=0

We add all the numbers together, and all the variables

-2A+6=0

We move all terms containing A to the left, all other terms to the right

-2A=-6

A=-6/-2

A=+3

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