A(n)=-6+(n-1)(5)

Solution for A(n)=-6+(n-1)(5) equation:

(A)=-6+(A-1)(5)

We move all terms to the left:

(A)-(-6+(A-1)(5))=0


We calculate terms in parentheses: -(-6+(A-1)5), so:

-6+(A-1)5

determiningTheFunctionDomain
(A-1)5-6

We multiply parentheses

5A-5-6

We add all the numbers together, and all the variables

5A-11

Back to the equation:

-(5A-11)


We get rid of parentheses

A-5A+11=0

We add all the numbers together, and all the variables

-4A+11=0

We move all terms containing A to the left, all other terms to the right

-4A=-11

A=-11/-4

A=2+3/4