A(b+c)=b(y-c)

Solution for A(b+c)=b(y-c) equation:

Simplifying
A(b + c) = b(y + -1c)
(b * A + c * A) = b(y + -1c)
(bA + cA) = b(y + -1c)

Reorder the terms:
bA + cA = b(-1c + y)
bA + cA = (-1c * b + y * b)
bA + cA = (-1bc + by)

Solving
bA + cA = -1bc + by

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add 'bc' to each side of the equation.
bA + bc + cA = -1bc + bc + by

Combine like terms: -1bc + bc = 0
bA + bc + cA = 0 + by
bA + bc + cA = by

Add '-1by' to each side of the equation.
bA + bc + -1by + cA = by + -1by

Combine like terms: by + -1by = 0
bA + bc + -1by + cA = 0

Add '-1cA' to each side of the equation.
bA + bc + -1by + cA + -1cA = 0 + -1cA

Combine like terms: cA + -1cA = 0
bA + bc + -1by + 0 = 0 + -1cA
bA + bc + -1by = 0 + -1cA
Remove the zero:
bA + bc + -1by = -1cA

Combine like terms: -1cA + cA = 0
bA + bc + -1by + cA = 0

The solution to this equation could not be determined.