A(3x2-2)=6x2+B

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Solution for A(3x2-2)=6x2+B equation: 



(3A^2-2)=6A^2+

We move all terms to the left:

(3A^2-2)-(6A^2+)=0

We get rid of parentheses

3A^2-6A^2-2-=0

We add all the numbers together, and all the variables

-3A^2=0

a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{-6}=0$

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