A(2A+10)=168

Solution for A(2A+10)=168 equation:

Simplifying
A(2A + 10) = 168

Reorder the terms:
A(10 + 2A) = 168
(10 * A + 2A * A) = 168
(10A + 2A2) = 168

Solving
10A + 2A2 = 168

Solving for variable 'A'.

Reorder the terms:
-168 + 10A + 2A2 = 168 + -168

Combine like terms: 168 + -168 = 0
-168 + 10A + 2A2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-84 + 5A + A2) = 0

Factor a trinomial.
2((-12 + -1A)(7 + -1A)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-12 + -1A)' equal to zero and attempt to solve:

Simplifying
-12 + -1A = 0

Solving
-12 + -1A = 0

Move all terms containing A to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -1A = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -1A = 0 + 12
-1A = 0 + 12

Combine like terms: 0 + 12 = 12
-1A = 12

Divide each side by '-1'.
A = -12

Simplifying
A = -12
Subproblem 2
Set the factor '(7 + -1A)' equal to zero and attempt to solve:

Simplifying
7 + -1A = 0

Solving
7 + -1A = 0

Move all terms containing A to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -1A = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1A = 0 + -7
-1A = 0 + -7

Combine like terms: 0 + -7 = -7
-1A = -7

Divide each side by '-1'.
A = 7

Simplifying
A = 7
Solution
A = {-12, 7}