A(22.1)+b(22.3)+c(23)=51

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Solution for A(22.1)+b(22.3)+c(23)=51 equation: 


Simplifying
A(22.1) + b(22.3) + c(23) = 51

Reorder the terms for easier multiplication:
22.1A + b(22.3) + c(23) = 51

Reorder the terms for easier multiplication:
22.1A + 22.3b + c(23) = 51

Reorder the terms for easier multiplication:
22.1A + 22.3b + 23c = 51

Solving
22.1A + 22.3b + 23c = 51

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Add '-22.3b' to each side of the equation.
22.1A + 22.3b + -22.3b + 23c = 51 + -22.3b

Combine like terms: 22.3b + -22.3b = 0.0
22.1A + 0.0 + 23c = 51 + -22.3b
22.1A + 23c = 51 + -22.3b

Add '-23c' to each side of the equation.
22.1A + 23c + -23c = 51 + -22.3b + -23c

Combine like terms: 23c + -23c = 0
22.1A + 0 = 51 + -22.3b + -23c
22.1A = 51 + -22.3b + -23c

Divide each side by '22.1'.
A = 2.307692308 + -1.009049774b + -1.040723982c

Simplifying
A = 2.307692308 + -1.009049774b + -1.040723982c

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