=y2+1.24y-0.1730=0

Solution for =y2+1.24y-0.1730=0 equation:

=y2+1.24y-0.1730=0

We move all terms to the left:

-(y2+1.24y-0.1730)=0

We add all the numbers together, and all the variables

-(+y^2+1.24y-0.1730)=0

We get rid of parentheses

-y^2-1.24y+0.1730=0

We add all the numbers together, and all the variables

-1y^2-1.24y+0.173=0

a = -1; b = -1.24; c = +0.173;
Δ = b2-4ac
Δ = -1.242-4·(-1)·0.173
Δ = 2.2296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.24)-\sqrt{2.2296}}{2*-1}=\frac{1.24-\sqrt{2.2296}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.24)+\sqrt{2.2296}}{2*-1}=\frac{1.24+\sqrt{2.2296}}{-2}
$