=4x2-20x+25

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Solution for =4x2-20x+25 equation: 



=4x^2-20x+25

We move all terms to the left:

-(4x^2-20x+25)=0

We get rid of parentheses

-4x^2+20x-25=0

a = -4; b = 20; c = -25;
Δ = b2-4ac
Δ = 202-4·(-4)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{-8}=2+1/2$

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