=3(a+1)(a+1)

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Solution for =3(a+1)(a+1) equation:


Simplifying
0 = 3(a + 1)(a + 1)

Reorder the terms:
0 = 3(1 + a)(a + 1)

Reorder the terms:
0 = 3(1 + a)(1 + a)

Multiply (1 + a) * (1 + a)
0 = 3(1(1 + a) + a(1 + a))
0 = 3((1 * 1 + a * 1) + a(1 + a))
0 = 3((1 + 1a) + a(1 + a))
0 = 3(1 + 1a + (1 * a + a * a))
0 = 3(1 + 1a + (1a + a2))

Combine like terms: 1a + 1a = 2a
0 = 3(1 + 2a + a2)
0 = (1 * 3 + 2a * 3 + a2 * 3)
0 = (3 + 6a + 3a2)

Solving
0 = 3 + 6a + 3a2

Solving for variable 'a'.

Combine like terms: 0 + -3 = -3
-3 + -6a + -3a2 = 3 + 6a + 3a2 + -3 + -6a + -3a2

Reorder the terms:
-3 + -6a + -3a2 = 3 + -3 + 6a + -6a + 3a2 + -3a2

Combine like terms: 3 + -3 = 0
-3 + -6a + -3a2 = 0 + 6a + -6a + 3a2 + -3a2
-3 + -6a + -3a2 = 6a + -6a + 3a2 + -3a2

Combine like terms: 6a + -6a = 0
-3 + -6a + -3a2 = 0 + 3a2 + -3a2
-3 + -6a + -3a2 = 3a2 + -3a2

Combine like terms: 3a2 + -3a2 = 0
-3 + -6a + -3a2 = 0

Factor out the Greatest Common Factor (GCF), '-3'.
-3(1 + 2a + a2) = 0

Factor a trinomial.
-3((1 + a)(1 + a)) = 0

Ignore the factor -3.

Subproblem 1

Set the factor '(1 + a)' equal to zero and attempt to solve: Simplifying 1 + a = 0 Solving 1 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + a = 0 + -1 Combine like terms: 1 + -1 = 0 0 + a = 0 + -1 a = 0 + -1 Combine like terms: 0 + -1 = -1 a = -1 Simplifying a = -1

Subproblem 2

Set the factor '(1 + a)' equal to zero and attempt to solve: Simplifying 1 + a = 0 Solving 1 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + a = 0 + -1 Combine like terms: 1 + -1 = 0 0 + a = 0 + -1 a = 0 + -1 Combine like terms: 0 + -1 = -1 a = -1 Simplifying a = -1

Solution

a = {-1, -1}

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