=3(2t-5)+4(t+3)

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Solution for =3(2t-5)+4(t+3) equation:


Simplifying
0 = 3(2t + -5) + 4(t + 3)

Reorder the terms:
0 = 3(-5 + 2t) + 4(t + 3)
0 = (-5 * 3 + 2t * 3) + 4(t + 3)
0 = (-15 + 6t) + 4(t + 3)

Reorder the terms:
0 = -15 + 6t + 4(3 + t)
0 = -15 + 6t + (3 * 4 + t * 4)
0 = -15 + 6t + (12 + 4t)

Reorder the terms:
0 = -15 + 12 + 6t + 4t

Combine like terms: -15 + 12 = -3
0 = -3 + 6t + 4t

Combine like terms: 6t + 4t = 10t
0 = -3 + 10t

Solving
0 = -3 + 10t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-10t' to each side of the equation.
0 + -10t = -3 + 10t + -10t
Remove the zero:
-10t = -3 + 10t + -10t

Combine like terms: 10t + -10t = 0
-10t = -3 + 0
-10t = -3

Divide each side by '-10'.
t = 0.3

Simplifying
t = 0.3

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