=-2(3x-2y)(5x+y)

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Solution for =-2(3x-2y)(5x+y) equation:


Simplifying
0 = -2(3x + -2y)(5x + y)

Multiply (3x + -2y) * (5x + y)
0 = -2(3x * (5x + y) + -2y * (5x + y))
0 = -2((5x * 3x + y * 3x) + -2y * (5x + y))

Reorder the terms:
0 = -2((3xy + 15x2) + -2y * (5x + y))
0 = -2((3xy + 15x2) + -2y * (5x + y))
0 = -2(3xy + 15x2 + (5x * -2y + y * -2y))
0 = -2(3xy + 15x2 + (-10xy + -2y2))

Reorder the terms:
0 = -2(3xy + -10xy + 15x2 + -2y2)

Combine like terms: 3xy + -10xy = -7xy
0 = -2(-7xy + 15x2 + -2y2)
0 = (-7xy * -2 + 15x2 * -2 + -2y2 * -2)
0 = (14xy + -30x2 + 4y2)

Solving
0 = 14xy + -30x2 + 4y2

Solving for variable 'x'.
Remove the zero:
-14xy + 30x2 + -4y2 = 14xy + -30x2 + 4y2 + -14xy + 30x2 + -4y2

Reorder the terms:
-14xy + 30x2 + -4y2 = 14xy + -14xy + -30x2 + 30x2 + 4y2 + -4y2

Combine like terms: 14xy + -14xy = 0
-14xy + 30x2 + -4y2 = 0 + -30x2 + 30x2 + 4y2 + -4y2
-14xy + 30x2 + -4y2 = -30x2 + 30x2 + 4y2 + -4y2

Combine like terms: -30x2 + 30x2 = 0
-14xy + 30x2 + -4y2 = 0 + 4y2 + -4y2
-14xy + 30x2 + -4y2 = 4y2 + -4y2

Combine like terms: 4y2 + -4y2 = 0
-14xy + 30x2 + -4y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-7xy + 15x2 + -2y2) = 0

Factor a trinomial.
2((3x + -2y)(5x + y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(3x + -2y)' equal to zero and attempt to solve: Simplifying 3x + -2y = 0 Solving 3x + -2y = 0 Move all terms containing x to the left, all other terms to the right. Add '2y' to each side of the equation. 3x + -2y + 2y = 0 + 2y Combine like terms: -2y + 2y = 0 3x + 0 = 0 + 2y 3x = 0 + 2y Remove the zero: 3x = 2y Divide each side by '3'. x = 0.6666666667y Simplifying x = 0.6666666667y

Subproblem 2

Set the factor '(5x + y)' equal to zero and attempt to solve: Simplifying 5x + y = 0 Solving 5x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. 5x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 5x + 0 = 0 + -1y 5x = 0 + -1y Remove the zero: 5x = -1y Divide each side by '5'. x = -0.2y Simplifying x = -0.2y

Solution

x = {0.6666666667y, -0.2y}

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