=-16t2+25t+6

Solution for =-16t2+25t+6 equation:

=-16t^2+25t+6

We move all terms to the left:

-(-16t^2+25t+6)=0

We get rid of parentheses

16t^2-25t-6=0

a = 16; b = -25; c = -6;
Δ = b2-4ac
Δ = -252-4·16·(-6)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{1009}}{2*16}=\frac{25-\sqrt{1009}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{1009}}{2*16}=\frac{25+\sqrt{1009}}{32}
$