=(x+5i)(x-5i)

Solution for =(x+5i)(x-5i) equation:

Simplifying
0 = (x + 5i)(x + -5i)

Reorder the terms:
0 = (5i + x)(x + -5i)

Reorder the terms:
0 = (5i + x)(-5i + x)

Multiply (5i + x) * (-5i + x)
0 = (5i * (-5i + x) + x(-5i + x))
0 = ((-5i * 5i + x * 5i) + x(-5i + x))

Reorder the terms:
0 = ((5ix + -25i2) + x(-5i + x))
0 = ((5ix + -25i2) + x(-5i + x))
0 = (5ix + -25i2 + (-5i * x + x * x))
0 = (5ix + -25i2 + (-5ix + x2))

Reorder the terms:
0 = (5ix + -5ix + -25i2 + x2)

Combine like terms: 5ix + -5ix = 0
0 = (0 + -25i2 + x2)
0 = (-25i2 + x2)

Solving
0 = -25i2 + x2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '25i2' to each side of the equation.
0 + 25i2 = -25i2 + 25i2 + x2
Remove the zero:
25i2 = -25i2 + 25i2 + x2

Combine like terms: -25i2 + 25i2 = 0
25i2 = 0 + x2
25i2 = x2

Divide each side by '25'.
i2 = 0.04x2

Simplifying
i2 = 0.04x2

Take the square root of each side:
i = {-0.2x, 0.2x}