=(x+2)+(y+2)+(z+2)+1

Solution for =(x+2)+(y+2)+(z+2)+1 equation:

Simplifying
0 = (x + 2) + (y + 2) + (z + 2) + 1

Reorder the terms:
0 = (2 + x) + (y + 2) + (z + 2) + 1

Remove parenthesis around (2 + x)
0 = 2 + x + (y + 2) + (z + 2) + 1

Reorder the terms:
0 = 2 + x + (2 + y) + (z + 2) + 1

Remove parenthesis around (2 + y)
0 = 2 + x + 2 + y + (z + 2) + 1

Reorder the terms:
0 = 2 + x + 2 + y + (2 + z) + 1

Remove parenthesis around (2 + z)
0 = 2 + x + 2 + y + 2 + z + 1

Reorder the terms:
0 = 2 + 2 + 2 + 1 + x + y + z

Combine like terms: 2 + 2 = 4
0 = 4 + 2 + 1 + x + y + z

Combine like terms: 4 + 2 = 6
0 = 6 + 1 + x + y + z

Combine like terms: 6 + 1 = 7
0 = 7 + x + y + z

Solving
0 = 7 + x + y + z

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
0 + -1x = 7 + x + y + -1x + z
Remove the zero:
-1x = 7 + x + y + -1x + z

Reorder the terms:
-1x = 7 + x + -1x + y + z

Combine like terms: x + -1x = 0
-1x = 7 + 0 + y + z
-1x = 7 + y + z

Divide each side by '-1'.
x = -7 + -1y + -1z

Simplifying
x = -7 + -1y + -1z