=(5z+2)(5z-2)

Solution for =(5z+2)(5z-2) equation:

Simplifying
0 = (5z + 2)(5z + -2)

Reorder the terms:
0 = (2 + 5z)(5z + -2)

Reorder the terms:
0 = (2 + 5z)(-2 + 5z)

Multiply (2 + 5z) * (-2 + 5z)
0 = (2(-2 + 5z) + 5z * (-2 + 5z))
0 = ((-2 * 2 + 5z * 2) + 5z * (-2 + 5z))
0 = ((-4 + 10z) + 5z * (-2 + 5z))
0 = (-4 + 10z + (-2 * 5z + 5z * 5z))
0 = (-4 + 10z + (-10z + 25z2))

Combine like terms: 10z + -10z = 0
0 = (-4 + 0 + 25z2)
0 = (-4 + 25z2)

Solving
0 = -4 + 25z2

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-25z2' to each side of the equation.
0 + -25z2 = -4 + 25z2 + -25z2
Remove the zero:
-25z2 = -4 + 25z2 + -25z2

Combine like terms: 25z2 + -25z2 = 0
-25z2 = -4 + 0
-25z2 = -4

Divide each side by '-25'.
z2 = 0.16

Simplifying
z2 = 0.16

Take the square root of each side:
z = {-0.4, 0.4}