=(4x-3)(4x+3)

Solution for =(4x-3)(4x+3) equation:

Simplifying
0 = (4x + -3)(4x + 3)

Reorder the terms:
0 = (-3 + 4x)(4x + 3)

Reorder the terms:
0 = (-3 + 4x)(3 + 4x)

Multiply (-3 + 4x) * (3 + 4x)
0 = (-3(3 + 4x) + 4x * (3 + 4x))
0 = ((3 * -3 + 4x * -3) + 4x * (3 + 4x))
0 = ((-9 + -12x) + 4x * (3 + 4x))
0 = (-9 + -12x + (3 * 4x + 4x * 4x))
0 = (-9 + -12x + (12x + 16x2))

Combine like terms: -12x + 12x = 0
0 = (-9 + 0 + 16x2)
0 = (-9 + 16x2)

Solving
0 = -9 + 16x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16x2' to each side of the equation.
0 + -16x2 = -9 + 16x2 + -16x2
Remove the zero:
-16x2 = -9 + 16x2 + -16x2

Combine like terms: 16x2 + -16x2 = 0
-16x2 = -9 + 0
-16x2 = -9

Divide each side by '-16'.
x2 = 0.5625

Simplifying
x2 = 0.5625

Take the square root of each side:
x = {-0.75, 0.75}