=(2x-3)(2x+3)

Solution for =(2x-3)(2x+3) equation:

Simplifying
0 = (2x + -3)(2x + 3)

Reorder the terms:
0 = (-3 + 2x)(2x + 3)

Reorder the terms:
0 = (-3 + 2x)(3 + 2x)

Multiply (-3 + 2x) * (3 + 2x)
0 = (-3(3 + 2x) + 2x * (3 + 2x))
0 = ((3 * -3 + 2x * -3) + 2x * (3 + 2x))
0 = ((-9 + -6x) + 2x * (3 + 2x))
0 = (-9 + -6x + (3 * 2x + 2x * 2x))
0 = (-9 + -6x + (6x + 4x2))

Combine like terms: -6x + 6x = 0
0 = (-9 + 0 + 4x2)
0 = (-9 + 4x2)

Solving
0 = -9 + 4x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x2' to each side of the equation.
0 + -4x2 = -9 + 4x2 + -4x2
Remove the zero:
-4x2 = -9 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-4x2 = -9 + 0
-4x2 = -9

Divide each side by '-4'.
x2 = 2.25

Simplifying
x2 = 2.25

Take the square root of each side:
x = {-1.5, 1.5}