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9z-16/6z=14
We move all terms to the left:
9z-16/6z-(14)=0
Domain of the equation: 6z!=0We multiply all the terms by the denominator
z!=0/6
z!=0
z∈R
9z*6z-14*6z-16=0
Wy multiply elements
54z^2-84z-16=0
a = 54; b = -84; c = -16;
Δ = b2-4ac
Δ = -842-4·54·(-16)
Δ = 10512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10512}=\sqrt{144*73}=\sqrt{144}*\sqrt{73}=12\sqrt{73}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-12\sqrt{73}}{2*54}=\frac{84-12\sqrt{73}}{108} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+12\sqrt{73}}{2*54}=\frac{84+12\sqrt{73}}{108} $
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