9y2-13y+4=0

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Solution for 9y2-13y+4=0 equation: 



9y^2-13y+4=0

a = 9; b = -13; c = +4;
Δ = b2-4ac
Δ = -132-4·9·4
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*9}=\frac{8}{18}
=4/9
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*9}=\frac{18}{18}
=1
$

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