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9y^2+6y-8=0
a = 9; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·9·(-8)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*9}=\frac{-24}{18} =-1+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*9}=\frac{12}{18} =2/3 $
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