9y-8+2(2y+4)=-5(y+3)

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Solution for 9y-8+2(2y+4)=-5(y+3) equation: 



9y-8+2(2y+4)=-5(y+3)

We move all terms to the left:

9y-8+2(2y+4)-(-5(y+3))=0

We multiply parentheses

9y+4y-(-5(y+3))+8-8=0



We calculate terms in parentheses: -(-5(y+3)), so:

-5(y+3)

We multiply parentheses

-5y-15

Back to the equation:

-(-5y-15)



We add all the numbers together, and all the variables

13y-(-5y-15)=0

We get rid of parentheses

13y+5y+15=0

We add all the numbers together, and all the variables

18y+15=0

We move all terms containing y to the left, all other terms to the right

18y=-15

y=-15/18

y=-5/6

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