9y-2(3y+13)+7=7-6(6y+8)

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Solution for 9y-2(3y+13)+7=7-6(6y+8) equation: 



9y-2(3y+13)+7=7-6(6y+8)

We move all terms to the left:

9y-2(3y+13)+7-(7-6(6y+8))=0

We multiply parentheses

9y-6y-(7-6(6y+8))-26+7=0



We calculate terms in parentheses: -(7-6(6y+8)), so:

7-6(6y+8)

determiningTheFunctionDomain
-6(6y+8)+7

We multiply parentheses

-36y-48+7

We add all the numbers together, and all the variables

-36y-41

Back to the equation:

-(-36y-41)



We add all the numbers together, and all the variables

3y-(-36y-41)-19=0

We get rid of parentheses

3y+36y+41-19=0

We add all the numbers together, and all the variables

39y+22=0

We move all terms containing y to the left, all other terms to the right

39y=-22

y=-22/39

y=-22/39

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