9y-(2y-3)=5(y-2)+24

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Solution for 9y-(2y-3)=5(y-2)+24 equation: 



9y-(2y-3)=5(y-2)+24

We move all terms to the left:

9y-(2y-3)-(5(y-2)+24)=0

We get rid of parentheses

9y-2y-(5(y-2)+24)+3=0



We calculate terms in parentheses: -(5(y-2)+24), so:

5(y-2)+24

We multiply parentheses

5y-10+24

We add all the numbers together, and all the variables

5y+14

Back to the equation:

-(5y+14)



We add all the numbers together, and all the variables

7y-(5y+14)+3=0

We get rid of parentheses

7y-5y-14+3=0

We add all the numbers together, and all the variables

2y-11=0

We move all terms containing y to the left, all other terms to the right

2y=11

y=11/2

y=5+1/2

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