9y-(2y-3)=(y-2)+2y

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Solution for 9y-(2y-3)=(y-2)+2y equation: 



9y-(2y-3)=(y-2)+2y

We move all terms to the left:

9y-(2y-3)-((y-2)+2y)=0

We get rid of parentheses

9y-2y-((y-2)+2y)+3=0



We calculate terms in parentheses: -((y-2)+2y), so:

(y-2)+2y

We add all the numbers together, and all the variables

2y+(y-2)

We get rid of parentheses

2y+y-2

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We add all the numbers together, and all the variables

7y-(3y-2)+3=0

We get rid of parentheses

7y-3y+2+3=0

We add all the numbers together, and all the variables

4y+5=0

We move all terms containing y to the left, all other terms to the right

4y=-5

y=-5/4

y=-1+1/4

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