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9y+5y(22y+8)=500
We move all terms to the left:
9y+5y(22y+8)-(500)=0
We multiply parentheses
110y^2+9y+40y-500=0
We add all the numbers together, and all the variables
110y^2+49y-500=0
a = 110; b = 49; c = -500;
Δ = b2-4ac
Δ = 492-4·110·(-500)
Δ = 222401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{222401}}{2*110}=\frac{-49-\sqrt{222401}}{220} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{222401}}{2*110}=\frac{-49+\sqrt{222401}}{220} $
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