9y+4=5((9y+4)/5)

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Solution for 9y+4=5((9y+4)/5) equation: 



9y+4=5((9y+4)/5)

We move all terms to the left:

9y+4-(5((9y+4)/5))=0

We multiply all the terms by the denominator


9y*5))-(5((9y+4)+4*5))=0

We add all the numbers together, and all the variables

9y*5))-(5((9y+4)=0

Wy multiply elements

45y^2=0

a = 45; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·45·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{90}=0$

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