9y+3=(y-5)+7

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Solution for 9y+3=(y-5)+7 equation: 



9y+3=(y-5)+7

We move all terms to the left:

9y+3-((y-5)+7)=0



We calculate terms in parentheses: -((y-5)+7), so:

(y-5)+7

We get rid of parentheses

y-5+7

We add all the numbers together, and all the variables

y+2

Back to the equation:

-(y+2)



We get rid of parentheses

9y-y-2+3=0

We add all the numbers together, and all the variables

8y+1=0

We move all terms containing y to the left, all other terms to the right

8y=-1

y=-1/8

y=-1/8

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