9y+33=2(y-9)

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Solution for 9y+33=2(y-9) equation: 



9y+33=2(y-9)

We move all terms to the left:

9y+33-(2(y-9))=0



We calculate terms in parentheses: -(2(y-9)), so:

2(y-9)

We multiply parentheses

2y-18

Back to the equation:

-(2y-18)



We get rid of parentheses

9y-2y+18+33=0

We add all the numbers together, and all the variables

7y+51=0

We move all terms containing y to the left, all other terms to the right

7y=-51

y=-51/7

y=-7+2/7

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