9y+2-3(-2y-1)=3(y-3)

Solution for 9y+2-3(-2y-1)=3(y-3) equation:

9y+2-3(-2y-1)=3(y-3)

We move all terms to the left:

9y+2-3(-2y-1)-(3(y-3))=0

We multiply parentheses

9y+6y-(3(y-3))+3+2=0


We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)


We add all the numbers together, and all the variables

15y-(3y-9)+5=0

We get rid of parentheses

15y-3y+9+5=0

We add all the numbers together, and all the variables

12y+14=0

We move all terms containing y to the left, all other terms to the right

12y=-14

y=-14/12

y=-1+1/6