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9x=3(-5+2x)+3x+15
We move all terms to the left:
9x-(3(-5+2x)+3x+15)=0
We add all the numbers together, and all the variables
9x-(3(2x-5)+3x+15)=0
We calculate terms in parentheses: -(3(2x-5)+3x+15), so:We add all the numbers together, and all the variables
3(2x-5)+3x+15
We add all the numbers together, and all the variables
3x+3(2x-5)+15
We multiply parentheses
3x+6x-15+15
We add all the numbers together, and all the variables
9x
Back to the equation:
-(9x)
=0
x=0/1
x=0
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