9x2=96x+

Solution for 9x2=96x+ equation:

9x^2=96x+

We move all terms to the left:

9x^2-(96x+)=0

We add all the numbers together, and all the variables

9x^2-(+96x)=0

We get rid of parentheses

9x^2-96x=0

a = 9; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·9·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*9}=\frac{0}{18}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*9}=\frac{192}{18}
=10+2/3
$