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9x^2=7x+6
We move all terms to the left:
9x^2-(7x+6)=0
We get rid of parentheses
9x^2-7x-6=0
a = 9; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·9·(-6)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{265}}{2*9}=\frac{7-\sqrt{265}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{265}}{2*9}=\frac{7+\sqrt{265}}{18} $
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